Can I get some clarification on why I would want to use this?
myVar = !!someOtherVar;
In non-strictly typed languages, the ! operator converts a value to a boolean. Doing it twice would be equivalent to saying
myVar = (boolean)someOtherVar
Note that this is not recommended for code clarity.
(Rewritten to clarify, simplify)
That statement performs a couple different actions:
myVar = // This portion is a regular assignment, it will store the value of the suffix
!!someOtherVar; // This portion is evaluated to a boolean result
The !!someOtherVar
, I assume, is what you're really asking about. The answer is simple: it performs two logical NOT operations against the truthiness (a Javascript'ism) of someOtherVar
.
In other words, if you understand the !
operator, this just combines two of them (!!
isn't a different operator). By doing this it essentially returns the boolean evaluation of someOtherVar
--in other words, it's a cast from whatever type someOtherVar
is to boolean
.
So... to walk through this, and pay attention to the result of myVar
:
myVar = someOtherVar; // myVar will be whatever type someOtherVar is
myVar = !someOtherVar; // myVar will *always be boolean, but the inverse of someOtherVar's truthiness
myVar = !!someOtherVar; // myVar will *always be boolean, and be the equivalent of someOtherVar's truthiness
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With