Why can a T* be passed in register, but a unique_ptr<T> cannot?

Question

I'm watching Chandler Carruth's talk in CppCon 2019:

There are no Zero-Cost Abstractions

in it, he gives the example of how he was surprised by just how much overhead you incur by using an std::unique_ptr<int> over an int*; that segment starts about at time point 17:25.

You can have a look at the compilation results of his example pair-of-snippets (godbolt.org) - to witness that, indeed, it seems the compiler is not willing to pass the unique_ptr value - which in fact in the bottom line is just an address - inside a register, only in straight memory.

One of the points Mr. Carruth makes at around 27:00 is that the C++ ABI requires by-value parameters (some but not all; perhaps - non-primitive types? non-trivially-constructible types?) to be passed in-memory rather than within a register.

My questions:

1. Is this actually an ABI requirement on some platforms? (which?) Or maybe it's just some pessimization in certain scenarios?
2. Why is the ABI like that? That is, if the fields of a struct/class fit within registers, or even a single register - why should we not be able to pass it within that register?
3. Has the C++ standards committee discussed this point in recent years, or ever?

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PS - So as not to leave this question with no code:

Plain pointer:

void bar(int* ptr) noexcept; void baz(int* ptr) noexcept;  void foo(int* ptr) noexcept {     if (*ptr > 42) {         bar(ptr);          *ptr = 42;      }     baz(ptr); } 

Unique pointer:

using std::unique_ptr; void bar(int* ptr) noexcept; void baz(unique_ptr<int> ptr) noexcept;  void foo(unique_ptr<int> ptr) noexcept {     if (*ptr > 42) {          bar(ptr.get());         *ptr = 42;      }     baz(std::move(ptr)); } 

Answer 1

1. Is this actually an ABI requirement, or maybe it's just some pessimization in certain scenarios?

One example is System V Application Binary Interface AMD64 Architecture Processor Supplement. This ABI is for 64-bit x86-compatible CPUs (Linux x86_64 architecure). It is followed on Solaris, Linux, FreeBSD, macOS, Windows Subsystem for Linux:

If a C++ object has either a non-trivial copy constructor or a non-trivial destructor, it is passed by invisible reference (the object is replaced in the parameter list by a pointer that has class INTEGER).

An object with either a non-trivial copy constructor or a non-trivial destructor cannot be passed by value because such objects must have well defined addresses. Similar issues apply when returning an object from a function.

Note, that only 2 general purpose registers can be used for passing 1 object with a trivial copy constructor and a trivial destructor, i.e. only values of objects with sizeof no greater than 16 can be passed in registers. See Calling conventions by Agner Fog for a detailed treatment of the calling conventions, in particular §7.1 Passing and returning objects. There are separate calling conventions for passing SIMD types in registers.

There are different ABIs for other CPU architectures.

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There is also Itanium C++ ABI which most compilers comply with (apart from MSVC), which requires:

If the parameter type is non-trivial for the purposes of calls, the caller must allocate space for a temporary and pass that temporary by reference.

A type is considered non-trivial for the purposes of calls if:

• it has a non-trivial copy constructor, move constructor, or destructor, or
• all of its copy and move constructors are deleted.

This definition, as applied to class types, is intended to be the complement of the definition in [class.temporary]p3 of types for which an extra temporary is allowed when passing or returning a type. A type which is trivial for the purposes of the ABI will be passed and returned according to the rules of the base C ABI, e.g. in registers; often this has the effect of performing a trivial copy of the type.

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2. Why is the ABI like that? That is, if the fields of a struct/class fit within registers, or even a single register - why should we not be able to pass it within that register?

It is an implementation detail, but when an exception is handled, during stack unwinding, the objects with automatic storage duration being destroyed must be addressable relative to the function stack frame because the registers have been clobbered by that time. Stack unwinding code needs objects' addresses to invoke their destructors but objects in registers do not have an address.

Pedantically, destructors operate on objects:

An object occupies a region of storage in its period of construction ([class.cdtor]), throughout its lifetime, and in its period of destruction.

and an object cannot exist in C++ if no addressable storage is allocated for it because object's identity is its address.

When an address of an object with a trivial copy constructor kept in registers is needed the compiler can just store the object into memory and obtain the address. If the copy constructor is non-trivial, on the other hand, the compiler cannot just store it into memory, it rather needs to call the copy constructor which takes a reference and hence requires the address of the object in the registers. The calling convention probably cannot depend whether the copy constructor was inlined in the callee or not.

Another way to think about this, is that for trivially copyable types the compiler transfers the value of an object in registers, from which an object can be recovered by plain memory stores if necessary. E.g.:

void f(long*); void g(long a) { f(&a); } 

on x86_64 with System V ABI compiles into:

g(long):                             // Argument a is in rdi.         push    rax                  // Align stack, faster sub rsp, 8.         mov     qword ptr [rsp], rdi // Store the value of a in rdi into the stack to create an object.         mov     rdi, rsp             // Load the address of the object on the stack into rdi.         call    f(long*)             // Call f with the address in rdi.         pop     rax                  // Faster add rsp, 8.         ret                          // The destructor of the stack object is trivial, no code to emit. 

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In his thought-provoking talk Chandler Carruth mentions that a breaking ABI change may be necessary (among other things) to implement the destructive move that could improve things. IMO, the ABI change could be non-breaking if the functions using the new ABI explicitly opt-in to have a new different linkage, e.g. declare them in extern "C++20" {} block (possibly, in a new inline namespace for migrating existing APIs). So that only the code compiled against the new function declarations with the new linkage can use the new ABI.

Note that ABI doesn't apply when the called function has been inlined. As well as with link-time code generation the compiler can inline functions defined in other translation units or use custom calling conventions.