"which in ruby": Checking if program exists in $PATH from ruby

Question

my scripts rely heavily on external programs and scripts. I need to be sure that a program I need to call exists. Manually, I'd check this using 'which' in the commandline.

Is there an equivalent to File.exists? for things in $PATH?

(yes I guess I could parse %x[which scriptINeedToRun] but that's not super elegant.

Thanks! yannick

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UPDATE: Here's the solution I retained:

 def command?(command)        system("which #{ command} > /dev/null 2>&1")  end 

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UPDATE 2: A few new answers have come in - at least some of these offer better solutions.

Update 3: The ptools gem has adds a "which" method to the File class.

Answer 1

True cross-platform solution, works properly on Windows:

# Cross-platform way of finding an executable in the $PATH. # #   which('ruby') #=> /usr/bin/ruby def which(cmd)   exts = ENV['PATHEXT'] ? ENV['PATHEXT'].split(';') : ['']   ENV['PATH'].split(File::PATH_SEPARATOR).each do |path|     exts.each do |ext|       exe = File.join(path, "#{cmd}#{ext}")       return exe if File.executable?(exe) && !File.directory?(exe)     end   end   nil end 

This doesn't use host OS sniffing, and respects $PATHEXT which lists valid file extensions for executables on Windows.

Shelling out to which works on many systems but not all.

Answer 2

Use find_executable method from mkmf which is included to stdlib.

require 'mkmf'  find_executable 'ruby' #=> "/Users/narkoz/.rvm/rubies/ruby-2.0.0-p0/bin/ruby"  find_executable 'which-ruby' #=> nil