Consider following program:
#include <iostream>
struct Test
{
Test(...)
{
std::cout<<"Variadic constructor\n";
}
};
int main()
{
Test t;
t={3,4,5};
}
I think it is variadic constructor. Does the C++ standard says that constructor can be variadic? What is the use of such constructor? What is the rationale for allowing variadic constructor?
Let's try to answer your questions one by one:
I think it is variadic constructor.
You are correct.
Does the C++ standard says that constructor can be variadic?
IANALL, but, I think so. Why not? Constructor is just a (member) function.
What is the use of such constructor?
Like any other variadic function - to pass a variable number of arguments. It also has the same problems, mostly no type safety as any other variadic function. For example, let's say you need a list of (C) strings, you could do something like See live demo here.
#include <iostream>
#include <cstdarg>
struct Test
{
Test(int n,...)
{
va_list va;
va_start(va, n);
for (int i = 0; i < n; ++i) {
char const *s = va_arg(va, char*);
std::cout<<"s=" << s << std::endl;
}
va_end(va);
}
};
int main()
{
Test t{3, "3","4","5"};
}
Keep in mind that for this to work, you need at least one "non-variadic" parameter. So a "pure variadic" constructor, like the one you show, doesn't make much sense in portable C++ code. For any particular platform, you may know how to access the parameters even without the non-variadic parameter, so, this might work:
Test t={"3","4","5", NULL};
What is the rationale for allowing variadic constructor?
"It's C compatible and someone might have a use of it", I guess. If you know your way around <cstdarg>
, it can be an effective tool. Of course, with C++11, you should most probably use variadic templates / perfect forwarding and initialization lists instead. But, with C++98 you didn't have these tools.
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