What is the relationship between event loop and Promise [duplicate]

Question

I am curious about the relationship between Event Loop and Promise.
The demo exposes the question. I expected the p1 fulfilled appear in the middle, since they queue a task to the same task queue and are executed one by one.

var p1 = new Promise(function(resolve, reject){
    resolve(1)
})
setTimeout(function(){
  console.log("will be executed at the top of the next Event Loop")
},0)
p1.then(function(value){
  console.log("p1 fulfilled")
})
setTimeout(function(){
  console.log("will be executed at the bottom of the next Event Loop")
},0)

The console result is:

p1 fulfilled
will be executed at the top of the next Event Loop
will be executed at the bottom of the next Event Loop

The visualized effect shows the promise.then's callback didn't go to the task queue of the Event Loop. It's right?

【NOTE: The question is not the same as Promise vs setTimeout, since it focus more on the relationship between Event Loop and Promise】

Answer 1

Each event loop has a microtask queue and a macrotask queue.

A microtask is a task that is originally to be queued on the microtask queue rather than a task queue. Refer to https://www.w3.org/TR/html51/webappapis.html#microtask-queue.

There are two kinds of microtasks:

• solitary callback microtasks, such as Promise，
• and compound microtasks, such as Object.observe, MutationObserver and process.nextTick in Node.js.

And the macrotask queue mainly contains setTimeout, setInterval, setImmediate, requestAnimationFrame, I/O in Nodejs.

In a event Loop, these two task queues will run in two steps:

1. First, check whether there is a macrotask (call it X) in old macrotask queue ;
2. If X exists and it is running, wait for it to go to the next step until it was complete; otherwise, goto the next step immediately;
3. Second, run all microtasks of the microtask queue;
4. and when run the microtasks, we can still add some more microtaks into the queue, these tasks will also run.

In your example:

1. First, your Promise initialize new Promise and resolve are synchronous;
2. and then synchronously add a setTimeout macroTask into the macrotask queue;
3. then synchronously add the microtask promise.then(function(){}) to the microtask queue, this task will run immediately, because the Promise initialize and resolve are synchronous, this task run before any macrotask; so, console.log the p1 fulfilled;
4. then add the second macrotask setTimeout to macrotask queue;
5. after this event loop ended, run the two macrotasks;

for this code:

setTimeout(function(){   console.log("will be executed at the top of the next Event Loop") },0) var p1 = new Promise(function(resolve, reject){     setTimeout(function(){resolve(1)},0) }); setTimeout(function(){     console.log("will be executed at the bottom of the next Event Loop") },0) for (var i = 0; i < 100; i++) {     (function(j){         p1.then(function(value){            console.log("promise then - " + j)         });     })(i) } 

the output order:

will be executed at the top of the next Event Loop promise then - 0 promise then - 1 promise then - 2 ... promise then - 99 will be executed at the bottom of the next Event Loop 

1. First add three macrotask setTimeout to macrotask queue, and a microtask promise.then() to the microtask queue;
2. run a macrotask;
3. If condition true run all microtasks, but it's false, so go to the next step;
4. run the second macrotask;
5. check whether the promise resolved or not, the condition is true, then run all microtasks;
6. go on to run other macrotasks;