There are some looooong and hungry algorithms for doing so, but as of yet I haven't come up with or found anything particularly fast.
The fastest way is to this is to use unsafe calls to manipulate the image memory directly using LockBits
. It sounds scary but it's pretty straight forward. If you search for LockBits you'll find plently of examples such as here.
The interesting bit is:
BitmapData originalData = originalBitmap.LockBits(
new Rectangle(0, 0, originalWidth, originalHeight),
ImageLockMode.ReadOnly,
PixelFormat.Format32bppRgb);
Once you have the BitmapData you can pass the pixels and map them into a new image (again using LockBits). This is significantly quicker than using the Graphics
API.
Here's what I ended up doing (after an extensive amount of continued research, and the helpful link provided by TheCodeKing):
public Image RotateImage(Image img, float rotationAngle)
{
// When drawing the returned image to a form, modify your points by
// (-(img.Width / 2) - 1, -(img.Height / 2) - 1) to draw for actual co-ordinates.
//create an empty Bitmap image
Bitmap bmp = new Bitmap((img.Width * 2), (img.Height *2));
//turn the Bitmap into a Graphics object
Graphics gfx = Graphics.FromImage(bmp);
//set the point system origin to the center of our image
gfx.TranslateTransform((float)bmp.Width / 2, (float)bmp.Height / 2);
//now rotate the image
gfx.RotateTransform(rotationAngle);
//move the point system origin back to 0,0
gfx.TranslateTransform(-(float)bmp.Width / 2, -(float)bmp.Height / 2);
//set the InterpolationMode to HighQualityBicubic so to ensure a high
//quality image once it is transformed to the specified size
gfx.InterpolationMode = InterpolationMode.HighQualityBicubic;
//draw our new image onto the graphics object with its center on the center of rotation
gfx.DrawImage(img, new PointF((img.Width / 2), (img.Height / 2)));
//dispose of our Graphics object
gfx.Dispose();
//return the image
return bmp;
}
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