What is the advantage of using forwarding references in range-based for loops?

Question

The only advantage I can see is when the sequence iterator returns a proxy reference and you need to operate on that reference in a non-const way. For example consider:

#include <vector>

int main()
{
    std::vector<bool> v(10);
    for (auto& e : v)
        e = true;
}

This doesn't compile because rvalue vector<bool>::reference returned from the iterator won't bind to a non-const lvalue reference. But this will work:

#include <vector>

int main()
{
    std::vector<bool> v(10);
    for (auto&& e : v)
        e = true;
}

All that being said, I wouldn't code this way unless you knew you needed to satisfy such a use case. I.e. I wouldn't do this gratuitously because it does cause people to wonder what you're up to. And if I did do it, it wouldn't hurt to include a comment as to why:

#include <vector>

int main()
{
    std::vector<bool> v(10);
    // using auto&& so that I can handle the rvalue reference
    //   returned for the vector<bool> case
    for (auto&& e : v)
        e = true;
}

Edit

This last case of mine should really be a template to make sense. If you know the loop is always handling a proxy reference, then auto would work as well as auto&&. But when the loop was sometimes handling non-proxy references and sometimes proxy-references, then I think auto&& would become the solution of choice.

Using auto&& or universal references with a range-based for-loop has the advantage that you captures what you get. For most kinds of iterators you'll probably get either a T& or a T const& for some type T. The interesting case is where dereferencing an iterator yields a temporary: C++ 2011 got relaxed requirements and iterators aren't necessarily required to yield an lvalue. The use of universal references matches the argument forwarding in std::for_each():

template <typename InIt, typename F>
F std::for_each(InIt it, InIt end, F f) {
    for (; it != end; ++it) {
        f(*it); // <---------------------- here
    }
    return f;
}

The function object f can treat T&, T const&, and T differently. Why should the body of a range-based for-loop be different? Of course, to actually take advantage of having deduced the type using universal references you'd need to pass them on correspondingly:

for (auto&& x: range) {
    f(std::forward<decltype(x)>(x));
}

Of course, using std::forward() means that you accept any returned values to be moved from. Whether objects like this makes much sense in non-template code I don't know (yet?). I can imagine that using universal references can offer more information to the compiler to do the Right Thing. In templated code it stays out of making any decision on what should happen with the objects.

I virtually always use auto&&. Why get bitten by an edge case when you don't have to? It's shorter to type too, and I simply find it more... transparent. When you use auto&& x, then you know that x is exactly *it, every time.