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enum { kFlag_FPS = 1 << 0, kFlag_Help = 1 << 1, kFlag_RedBlue3D = 1 << 2, } I am trying to understand what this code is I don't quite know what:
1 << 0 means?
Any help is greatly appreciated!
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The << operator shifts the left-hand value left by the (right-hand value) bits. Your example does nothing! 1 shifted 0 bits to the left is still 1. However, 1 << 1 is 2, 1 << 2 is 4, etc.
The bitwise shift operators are the right-shift operator ( >> ), which moves the bits of an integer or enumeration type expression to the right, and the left-shift operator ( << ), which moves the bits to the left.
1 in binary is 0001 , then bitshifting it by 0 won't do anything, which aligns with what you observed. So any number x << 0 is equivalent to x * 2^0 , which is x * 1 , which is just x .
From MSDN - Shift Operators: >> and <<
The left-shift operator causes the bit pattern in the first operand to be shifted to the left by the number of bits specified by the second operand. Bits vacated by the shift operation are zero-filled. This is a logical shift instead of a shift-and-rotate operation.
This means that the user is taking the bits value of 1 and shifting the bits to the left based on the right number.
That means that in this case, their values will look like this in binary.
1 << 0 = `0000 0001` 1 << 1 = `0000 0010` 1 << 2 = `0000 0100` The first shift is not necessary, but it looks more consistent with the rest.
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1 << 0 is 1 shifted to the left by 0 positions, which is just 1.
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