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WebView link click open default browser

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How do I open a link in WebView?

Within the shouldOverrideUrlLoading() method simply get the URL from the request and pass into the Intent. See the full example.

How do I open WebView in Chrome?

# Open a WebView in DevToolsThe chrome://inspect page displays a list of debug-enabled WebViews on your device. To start debugging, click inspect below the WebView you want to debug. Use DevTools as you would for a remote browser tab.

Which browser does WebView use?

Browservio​ by XDA Senior Member tipzrickycheung is one such browser, and it offers many useful features. Not only is the app free and open-source, but it also uses Android's built-in WebView component as its backend to keep the footprint low.


I had to do the same thing today and I have found a very useful answer on StackOverflow that I want to share here in case someone else needs it.

Source (from sven)

webView.setWebViewClient(new WebViewClient(){
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url != null && (url.startsWith("http://") || url.startsWith("https://"))) {
            view.getContext().startActivity(
                new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
            return true;
        } else {
            return false;
        }
    }
});

WebView webview = (WebView) findViewById(R.id.webview);
webview.loadUrl(https://whatoplay.com/);

You don't have to include this code.

// webview.setWebViewClient(new WebViewClient());

Instead use below code.

webview.setWebViewClient(new WebViewClient()
{
  public boolean shouldOverrideUrlLoading(WebView view, String url)
  {
    String url2="https://whatoplay.com/";
     // all links  with in ur site will be open inside the webview 
     //links that start ur domain example(http://www.example.com/)
    if (url != null && url.startsWith(url2)){
      return false;
    } 
     // all links that points outside the site will be open in a normal android browser
    else
    {
      view.getContext().startActivity(
      new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
      return true;
    }
  }
});

You only need to add the following line

yourWebViewName.setWebViewClient(new WebViewClient());

Check this for official documentation.


you can use Intent for this:

Intent browserIntent = new Intent("android.intent.action.VIEW", Uri.parse("your Url"));
startActivity(browserIntent);

You can use an Intent for this:

Uri uriUrl = Uri.parse("http://www.google.com/"); 
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);  
startActivity(launchBrowser);  

As this is one of the top questions about external redirect in WebView, here is a "modern" solution on Kotlin:

webView.webViewClient = object : WebViewClient() {
        override fun shouldOverrideUrlLoading(
            view: WebView?,
            request: WebResourceRequest?
        ): Boolean {
            val url = request?.url ?: return false
            //you can do checks here e.g. url.host equals to target one
            startActivity(Intent(Intent.ACTION_VIEW, url))
            return true
        }
    }