Code analysis:
ON_NOTIFY(TCN_SELCHANGE, IDC_TAB_HISTORY_TYPE,
&CAssignHistoryDlg::OnTcnSelchangeTabHistoryType)
Warning C26454:
Arithmetic overflow: '-' operation produces a negative unsigned result at compile time (io.5).
The definition of TCN_SELCHANGE
is:
#define TCN_FIRST (0U-550U)
#define TCN_SELCHANGE (TCN_FIRST - 1)
I can't see what else I can do!
//windows header file:
#define TCN_FIRST (0U-550U)
#define TCN_SELCHANGE (TCN_FIRST - 1)
//user file:
...
unsigned int i = TCN_SELCHANGE;
Above code is valid in C++, it should compile without any warning. There is no overflow, that's just meant to be -550U
It would be more clear if they wrote it as #define TCN_FIRST 0xFFFFFDDA
or 0xFFFFFFFFU-549U
Code Analysis seems to uses a different method and sees an overflow.
Possible solution:
Disable the warning in code:
#pragma warning( push )
#pragma warning( disable : 26454 )
BEGIN_MESSAGE_MAP(CMyDialog, CDialogEx)
ON_NOTIFY(TCN_SELCHANGE, IDC_TAB1, OnTcnSelchangeTabHistoryType)
END_MESSAGE_MAP()
#pragma warning( pop )
Or, disable the warning in Code Analysis rule
Use the code analysis rule set editor
You are trying to subtract a larger unsigned value from a smaller unsigned value and it's causing the result to wrap past zero. In your case, I assume TCN_FIRST is defined as 0 so setting TCN_SELCHANGE to one will fix the problem.
You should also be using constexpr
or const
instead of defines anyway.
According to MSDN:
Arithmetic overflow checks in C++ Core Check
C26451 RESULT_OF_ARITHMETIC_OPERATION_CAST_TO_LARGER_SIZE :[operator] operation wraps past 0 and produces a large unsigned number at compile time. This warning indicates that the subtraction operation produces a negative result which was evaluated in an unsigned context. This causes the result to wrap past 0 and produce a really large unsigned number, which can result in unintended overflows.
1 // Example source:
2 unsigned int negativeunsigned() {
3 const unsigned int x = 1u - 2u; // C26454 reported here
4 return x;
5 }
1 // Corrected source:
2 unsigned int negativeunsigned() {
3 const unsigned int x = 4294967295; // OK
4 return x;
5 }
In the corrected source, a positive value was assigned to the unsigned result.
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