How could I make my code wait until the task in DispatchQueue finishes? Does it need any CompletionHandler or something?
func myFunction() {
var a: Int?
DispatchQueue.main.async {
var b: Int = 3
a = b
}
// wait until the task finishes, then print
print(a) // - this will contain nil, of course, because it
// will execute before the code above
}
I'm using Xcode 8.2 and writing in Swift 3.
The Task. WaitAll() method in C# is used to wait for the completion of all the objects of the Task class. The Task class represents an asynchronous task in C#. We can start threads with the Task class and wait for the threads to finish with the Task.
Wait is a synchronization method that causes the calling thread to wait until the current task has completed. If the current task has not started execution, the Wait method attempts to remove the task from the scheduler and execute it inline on the current thread.
The Run method allows you to create and execute a task in a single method call and is a simpler alternative to the StartNew method. It creates a task with the following default values: Its cancellation token is CancellationToken.
'Wait' means to pass the time until an anticipated event occurs, whereas 'await' means to wait for something with a hope.
Use DispatchGroup
s to achieve this. You can either get notified when the group's enter()
and leave()
calls are balanced:
func myFunction() {
var a: Int?
let group = DispatchGroup()
group.enter()
DispatchQueue.main.async {
a = 1
group.leave()
}
// does not wait. But the code in notify() gets run
// after enter() and leave() calls are balanced
group.notify(queue: .main) {
print(a)
}
}
or you can wait:
func myFunction() {
var a: Int?
let group = DispatchGroup()
group.enter()
// avoid deadlocks by not using .main queue here
DispatchQueue.global(attributes: .qosDefault).async {
a = 1
group.leave()
}
// wait ...
group.wait()
print(a) // you could also `return a` here
}
Note: group.wait()
blocks the current queue (probably the main queue in your case), so you have to dispatch.async
on another queue (like in the above sample code) to avoid a deadlock.
In Swift 3, there is no need for completion handler when DispatchQueue
finishes one task.
Furthermore you can achieve your goal in different ways
One way is this:
var a: Int?
let queue = DispatchQueue(label: "com.app.queue")
queue.sync {
for i in 0..<10 {
print("Ⓜ️" , i)
a = i
}
}
print("After Queue \(a)")
It will wait until the loop finishes but in this case your main thread will block.
You can also do the same thing like this:
let myGroup = DispatchGroup()
myGroup.enter()
//// Do your task
myGroup.leave() //// When your task completes
myGroup.notify(queue: DispatchQueue.main) {
////// do your remaining work
}
One last thing: If you want to use completionHandler when your task completes using DispatchQueue, you can use DispatchWorkItem
.
Here is an example how to use DispatchWorkItem
:
let workItem = DispatchWorkItem {
// Do something
}
let queue = DispatchQueue.global()
queue.async {
workItem.perform()
}
workItem.notify(queue: DispatchQueue.main) {
// Here you can notify you Main thread
}
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