Using XPath to parse an XML document

Question

Lets say I have the following xml (a quick example)

<rows>
   <row>
      <name>one</name>
   </row>
   <row>
      <name>two</name>
   </row>
</rows>

I am trying to parse this by using XmlDocument and XPath (ultimately so I can make a list of rows).

For example...

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

foreach(XmlNode row in doc.SelectNodes("//row"))
{
   string rowName = row.SelectSingleNode("//name").InnerText;
}

Why, within my foreach loop, is rowName always "one"? I am expecting it to be "one" on the first iteration and "two" on the second.

It seems that //name gets the first instance in the document, rather than the first instance in the row as I would expect. After all, I am calling the method on the "row" node. If this is "just how it works" then can anybody please explain how I could change it to work to my needs?

Thank you

Answer 1

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

foreach(XmlNode row in doc.SelectNodes("//row"))
{
   var rowName = row.SelectSingleNode("name");
}

Is the code you posted actually correct? I get a compile error on row.SelectNode() as it isn't a member of XmlNode.

Anyway, my example above works, but assumes only a single <name> node within the <row> node so you may need to use SelectNodes() instead of SelectSingleNode() if that is not the case.

As others have shown, use .InnerText to get just the value.

Answer 2

Use LINQ to XML. Include using System.Xml.Linq; in your code file and then do the following code to get your list

XDocument xDoc = XDocument.Load(filepath);
IEnumerable<XElement> xNames;

xNames = xDoc.Descendants("name");

That will give you a list of the name elements. Then if you want to turn that into a List<string> just do this:

List<string> list = new List<string>();
foreach (XElement element in xNames)
{
    list.Add(element.value);
}