Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Using the reserved word "class" as field name in Django and Django REST Framework

Description of the problem

Taxonomy is the science of defining and naming groups of biological organisms on the basis of shared characteristics. Organisms are grouped together into taxa (singular: taxon) and these groups are given a taxonomic rank. The principal ranks in modern use are domain, kingdom, phylum, class, order, family, genus and species. More information on Taxonomy and Taxonomic ranks in Wikipedia.

Following the example for the red fox in the article Taxonomic rank in Wikipedia I need to create a JSON output like this:

{
    "species": "vulpes",
    "genus": "Vulpes",
    "family": "Canidae",
    "order": "Carnivora",
    "class": "Mammalia",
    "phylum": "Chordata",
    "kingdom": "Animalia",
    "domain": "Eukarya"
}

Since Django REST Framework creates the keys based on the field names, the problem arises with the taxonomic rank class (bold in the example) as it is a reserved word in Python and can't be used as a variable name.

What I have tried

A model class created in Django would look like this:

class Species(models.Model):
    species = models.CharField()
    genus = models.CharField()
    family = models.CharField()
    # class = models.CharField() - class is reserved word in Python
    # class_ = models.CharField() - Django doesn't allow field names
    # ending with underscore. That wouldn't be either a satisfying solution.
    # further fields

Question

Is there any possible way to solve this problem and generate the desired output? If not, what is the best practice to work around this problem?

like image 760
cezar Avatar asked Dec 04 '17 09:12

cezar


People also ask

Is field a reserved word in Python?

Answer is Simply No, Because Language only has the authority to own anything. Python is the owner of the house The Django guy is paying rent to Python guy.

What is write only field Django REST framework?

From DRF v3 onwards, setting a field as read-only or write-only can use serializer field core arguments mentioned as follows. write_only. Set this to True to ensure that the field may be used when updating or creating an instance, but is not included when serializing the representation.

What is the best authentication for Django REST framework?

JSON Web Token (JWT) Authentication.

Is Django and Django REST framework same?

Django is the web development framework in python whereas the Django Rest Framework is the library used in Django to build Rest APIs. Django Rest Framework is especially designed to make the CRUD operations easier to design in Django. Django Rest Framework makes it easy to use your Django Server as an REST API.


4 Answers

You can set the property of a class via strings as such:

class SpeciesSerializer(serializers.Serializer):
    species = serializers.CharField()
    genus = serializers.CharField()
    family = serializers.CharField()
    vars()['class'] = serializers.CharField()
like image 94
Bennie van Eeden Avatar answered Oct 13 '22 21:10

Bennie van Eeden


You can rename field in the overloaded version of get_fields() method

class MySerializer(serializers.Serializer):
    class_ = serializers.ReadOnlyField()

    def get_fields(self):
        result = super().get_fields()
        # Rename `class_` to `class`
        class_ = result.pop('class_')
        result['class'] = class_
        return result
like image 26
dtatarkin Avatar answered Oct 13 '22 23:10

dtatarkin


You can do it like below

class SpeciesSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = Species
        fields = (
            'url', 'id', 'canonical_name', 'slug',  'species', 'genus',
            'subfamily', 'family', 'order','class', 'phylum',
            'ncbi_id', 'ncbi_taxonomy',
        )
        read_only_fields = ('slug',)
        extra_kwargs = {
            'url': {'lookup_field': 'slug'}
        }

SpeciesSerializer._declared_fields["class"] = serializers.CharField(source="class_name")

As explained in below answer

https://stackoverflow.com/a/47717441/2830850

like image 6
Tarun Lalwani Avatar answered Oct 13 '22 22:10

Tarun Lalwani


Other software developers in the field of Bioinformatics might be interested in a solution of this problem, so I post here my approach as suggested by Alasdair.

The goal is to create a model for a living species, for the sake of simplicity let's say an animal, and create an endpoint with Django REST Framework representing the correct taxonomic ranks.

models.py

from django.db import models

class Animal(models.Model):
    canonical_name = models.CharField(max_length=100, unique=True)
    species = models.CharField(max_length=60, unique=True)
    genus = models.CharField(max_length=30)
    family = models.CharField(max_length=30)
    order = models.CharField(max_length=30)
    # we can't use class as field name
    class_name = models.CharField('Class', db_column='class', max_length=30)
    phylum = models.CharField(max_length=30)
    # we don't need to define kingdom and domain
    # it's clear that it is an animal and eukaryote

    def __str__(self):
        return '{} ({})'.format(self.canonical_name, self.species)

serializers.py

from collections import OrderedDict

from rest_framework import serializers

from .models import Species

class SpeciesSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = Animal
        fields = ('url', 'id', 'canonical_name', 'species', 'genus',
            'subfamily', 'family', 'order', 'class_name', 'phylum')

    def to_representation(self, obj):
        # call the parent method and get an OrderedDict
        data = super(SpeciesSerializer, self).to_representation(obj)
        # generate a list of the keys and replace the key 'class_name'
        keys = list(data.keys())
        keys.insert(keys.index('class_name'), 'class')
        keys.remove('class_name')
        # remove 'class_name' and assign its value to a new key 'class'
        class_name = data.pop('class_name')
        data.update({'class': class_name})
        # create new OrderedDict with the order given by the keys
        response = OrderedDict((k, data[k]) for k in keys)
        return response

The method to_representation helps us to manipulate the output. I have put some extra work here to get the taxonomic ranks in the desired order.

Thus for the red fox the output looks like this:

Red fox (Vulpes vulpes)

{
    "url": "http://localhost:8000/animal/1",
    "id": 1,
    "canonical_name": "Red fox",
    "species": "Vulpes vulpes",
    "genus": "Vulpes",
    "family": "Canidae",
    "order": "Carnivora",
    "class": "Mammalia",
    "phylum": "Chordata"
}

It is a simplified example and in reality you'd have many more fields or possibly a model for every taxonomic rank, but somewhere you might come across the conflict between the reserved word class and the taxonomic rank class.
I hope this can help other people too.

like image 5
cezar Avatar answered Oct 13 '22 22:10

cezar