Using ls, how to list files without printing the extension (the part after the dot)?

Question

Suppose I have a directory with some files:

$ ls
a.c  b.c  e.c  k.cpp  s.java

How can I display the result without the file extension(the part following the dot, including that dot)? Like this:

$ <some command>
a
b
e
k
s

Answer 1

using sed?

ls -1 | sed -e 's/\..*$//'

Answer 2

ls | while read fname 
do
    echo ${fname%%.*}
done

Try that.

Answer 3

ls -a | cut -d "." -f 1

man (1) cut

Very handy, the -d switch defines the delimiter and the -f which field you want.

EDIT: Include riverfall's scenario is also piece of cake as cut can start also from the end, though the logic is somewhat different. Here an example with a bunch of files with random names, some with two dots, some with a single dot and some without extension:

runlevel0@ubuntu:~/test$ ls
test.001.rpx  test.003.rpx  test.005.rpx  test.007.rpx  test.009.rpx  testxxx
test.002.rpx  test.004.rpx  test.006.rpx  test.008.rpx  test_nonum    test_xxx.rtv


runlevel0@ubuntu:~/test$ ls | cut  -d "." -f -2
test.001
test.002
test.003
test.004
test.005
test.006
test.007
test.008
test.009
test_nonum
testxxx
test_xxx.rtv

Using the minus before the field number makes it eliminate all BUT the indicated fields (1,2 in this case) and putting it behind makes it start counting from the end.

This same notation can be used for offset and characters besides of fields (see the man page)

Answer 4

If you already know the extension of the file, you can use basename, from the man page:

basename - strip directory and suffix from filenames

Unfortunately, it's mostly useful if you're trying to filter a single extension, in your case the command is:

basename -s .c -a $(ls *.c) && basename -s .cpp -a $(ls *.cpp) && basename -s .java -a $(ls *.java)

output:

a
b
e
k
s