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Using escaped_list_separator with boost split

I am playing around with the boost strings library and have just come across the awesome simplicity of the split method.

  string delimiters = ",";
  string str = "string, with, comma, delimited, tokens, \"and delimiters, inside a quote\"";
  // If we didn't care about delimiter characters within a quoted section we could us
  vector<string> tokens;  
  boost::split(tokens, str, boost::is_any_of(delimiters));
  // gives the wrong result: tokens = {"string", " with", " comma", " delimited", " tokens", "\"and delimiters", " inside a quote\""}

Which would be nice and concise... however it doesn't seem to work with quotes and instead I have to do something like the following

string delimiters = ",";
string str = "string, with, comma, delimited, tokens, \"and delimiters, inside a quote\"";
vector<string> tokens; 
escaped_list_separator<char> separator("\\",delimiters, "\"");
typedef tokenizer<escaped_list_separator<char> > Tokeniser;
Tokeniser t(str, separator);
for (Tokeniser::iterator it = t.begin(); it != t.end(); ++it)
    tokens.push_back(*it);
// gives the correct result: tokens = {"string", " with", " comma", " delimited", " tokens", "\"and delimiters, inside a quote\""}

My question is can split or another standard algorithm be used when you have quoted delimiters? Thanks to purpledog but I already have a non-deprecated way of achieving the desired outcome, I just think that it's quite cumbersome and unless I could replace it with a simpler more elegant solution I wouldn't use it in general without first wrapping it in yet another method.

EDIT: Updated code to show results and clarify question.

like image 273
Jamie Cook Avatar asked Feb 28 '23 17:02

Jamie Cook


1 Answers

It doesn't seem that there is any simple way to do this using the boost::split method. The shortest piece of code I can find to do this is

vector<string> tokens; 
tokenizer<escaped_list_separator<char> > t(str, escaped_list_separator<char>("\\", ",", "\""));
BOOST_FOREACH(string s, escTokeniser)
    tokens.push_back(s);  

which is only marginally more verbose than the original snippet

vector<string> tokens;  
boost::split(tokens, str, boost::is_any_of(","));
like image 132
Jamie Cook Avatar answered Mar 11 '23 12:03

Jamie Cook