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Using a DisplayTemplate (with DisplayFor) for each item in a collection

I have created a DisplayTemplate for a Comment class, and placed it inside Comment/DisplayTemplates/Comment.cshtml.

Comment.cshtml is properly typed:

@model Comment

Then, I have a partial view that takes an IEnumerable<Comment> for model. In there I loop through the collection and would like to use the DisplayTemplate for the Comment class. The view, in its integrity:

@model IEnumerable<Comment>

@foreach (var comment in Model.Where(c => c.Parent == null)) { 
    @Html.DisplayFor(model => comment)
}

However, I get an error on the Html.DisplayFor line:

The model item passed into the dictionary is of type 'System.Int32', but this dictionary requires a model item of type 'System.String'.

How can I invoke the DisplayTemplate for each item in the foreach loop?

like image 727
Sergi Papaseit Avatar asked Apr 13 '11 15:04

Sergi Papaseit


2 Answers

Instead of having a view that take an IEnumerable<Comment> and that all it does is loop through the collection and call the proper display template simply:

@Html.DisplayFor(x => x.Comments)

where the Comments property is an IEnumerable<Comment> which will automatically do the looping and render the Comment.cshtml display template for each item of this collection.

Or if you really need such a view (don't know why) you could simply:

@model IEnumerable<Comment>
@Html.DisplayForModel()

As far as the Where clause you are using in there you should simply remove it and delegate this task to the controller. It's the controller's responsibility to prepare the view model, not the view performing such tasks.

like image 116
Darin Dimitrov Avatar answered Nov 03 '22 10:11

Darin Dimitrov


While the accepted answer works well most of the time, there are other cases in which we need to be aware of the element's index when rendering (i.e. add custom javascript that generates references to each element based on their index).

In that case, DisplayFor can still be used within the loop like this:

@model IEnumerable<Comment>

@for (int index = 0; index < Model.Count(); index++)
{
     @Html.DisplayFor(model => model[index])
}
like image 21
Fernando Neira Avatar answered Nov 03 '22 10:11

Fernando Neira