How to set Accept and Accept-Language header fields?

Question

I can set Request.Content-Type = ... , Request.Content-Length = ...

How to set Accept and Accept-Language?

I want to upload a file (RFC 1867) and need to create a request like this:

 POST /test-upload.php.xml HTTP/1.1 Host: example.com User-Agent: Mozilla/5.0 (Windows NT 5.2; WOW64; rv:2.0.1) Gecko/20100101 Firefox/4.0.1 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: tr-tr,tr;q=0.8,en-us;q=0.5,en;q=0.3 Accept-Encoding: gzip, deflate Accept-Charset: ISO-8859-9,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Content-Type: multipart/form-data; boundary=---------------------------21724139663430 Content-Length: 56048 

Answer 1

Take a look at Accept property:

HttpWebRequest myHttpWebRequest=(HttpWebRequest)WebRequest.Create(myUri); myHttpWebRequest.Accept="image/*";     HttpWebResponse myHttpWebResponse=          (HttpWebResponse)myHttpWebRequest.GetResponse(); 

This MSDN article shows how to add custom headers to your request:

//Get the headers associated with the request. WebHeaderCollection myWebHeaderCollection = myHttpWebRequest.Headers;      //Add the Accept-Language header (for Danish) in the request. myWebHeaderCollection.Add("Accept-Language:da");  //Include English in the Accept-Langauge header.  myWebHeaderCollection.Add("Accept-Language","en;q=0.8"); 

Answer 2

When you want to set the Accept type and content type, just cast the webrequest to HttpwebRequest

var webreq= (HttpWebRequest)WebRequest.Create(requestUri); webreq.Method = "POST"; webreq.Accept = "application/json"; webreq.ContentType = "application/json";