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Use xslt replace function to replace a word with an element

Tags:

xslt

xslt-2.0

I want to usw the XSLT replace function to replace words in a text with

<strong>word</strong>.

I wrote the following template:

<xsl:template name="make-bold">
  <xsl:param name="text"/>
  <xsl:param name="word"/>
  <xsl:variable name="replacement">
     <strong><xsl:value-of select="$word"/></strong>
  </xsl:variable>
  <xsl:value-of select="replace($text, $word,  $replacement )" />
</xsl:template>

Unfortunately, and are not rendered, althoug the rest works.

Could anyone help me?

Best, Suidu

like image 854
Suidu Avatar asked Nov 07 '25 06:11

Suidu


1 Answers

Well the replace function http://www.w3.org/TR/xpath-functions/#func-replace takes a string and returns a string. You seem to want to create an element node, not a simple string. In that case using analyze-string http://www.w3.org/TR/xslt20/#analyze-string instead of replace could help.

Here is a sample XSLT 2.0 stylesheet:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="xs"
  version="2.0">

  <xsl:output method="html" indent="no"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@*, node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="p">
    <xsl:copy>
      <xsl:apply-templates select="@*"/>
      <xsl:apply-templates select="text()" mode="wrap">
        <xsl:with-param name="words" as="xs:string+" select="('foo', 'bar')"/>
      </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="text()" mode="wrap">
    <xsl:param name="words" as="xs:string+"/>
    <xsl:param name="wrapper-name" as="xs:string" select="'strong'"/>
    <xsl:analyze-string select="." regex="{string-join($words, '|')}">
      <xsl:matching-substring>
        <xsl:element name="{$wrapper-name}">
          <xsl:value-of select="."/>
        </xsl:element>
      </xsl:matching-substring>
      <xsl:non-matching-substring>
        <xsl:value-of select="."/>
      </xsl:non-matching-substring>
    </xsl:analyze-string>
  </xsl:template>

</xsl:stylesheet>

When you run that with an XSLT 2.0 processor like Saxon 9 against the following input sample

<html>
  <body>
    <p>This is an example with foo and bar words.</p>
  </body>
</html>

the output is as follows:

<html>
  <body>
    <p>This is an example with <strong>foo</strong> and <strong>bar</strong> words.</p>
  </body>
</html>
like image 176
Martin Honnen Avatar answered Nov 11 '25 11:11

Martin Honnen



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