'map' preserves the number of elements, so using it on a Tuple seems sensible.
My attempts so far:
scala> (3,4).map(_*2) error: value map is not a member of (Int, Int) (3,4).map(_*2) ^ scala> (3,4).productIterator.map(_*2) error: value * is not a member of Any (3,4).productIterator.map(_*2) ^ scala> (3,4).productIterator.map(_.asInstanceOf[Int]*2) res4: Iterator[Int] = non-empty iterator scala> (3,4).productIterator.map(_.asInstanceOf[Int]*2).toList res5: List[Int] = List(6, 8)
It looks quite painful... And I haven't even begun to try to convert it back to a tuple.
Am I doing it wrong? Could the library be improved?
In general, the element types of a tuple aren't the same, so map doesn't make sense. You can define a function to handle the special case, though:
scala> def map[A, B](as: (A, A))(f: A => B) = as match { case (a1, a2) => (f(a1), f(a2)) } map: [A,B](as: (A, A))(f: (A) => B)(B, B) scala> val p = (1, 2) p: (Int, Int) = (1,2) scala> map(p){ _ * 2 } res1: (Int, Int) = (2,4)
You could use the Pimp My Library pattern to call this as p.map(_ * 2)
.
UPDATE
Even when the types of the elements are not the same, Tuple2[A, B]
is a Bifunctor, which can be mapped with the bimap
operation.
scala> import scalaz._ import scalaz._ scala> import Scalaz._ import Scalaz._ scala> val f = (_: Int) * 2 f: (Int) => Int = <function1> scala> val g = (_: String) * 2 g: (String) => String = <function1> scala> f <-: (1, "1") :-> g res12: (Int, String) = (2,11)
UPDATE 2
http://gist.github.com/454818
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