Is there a simple method I'm missing in urllib
or other library for this task? URL encoding replaces unsafe ASCII characters with a "%" followed by two hexadecimal digits.
Here's an example of an input and my expected output:
Mozilla/5.0 (Linux; U; Android 4.0; xx-xx; Galaxy Nexus Build/IFL10C) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30 Mozilla%2F5.0+%28Linux%3B+U%3B+Android+4.0%3B+xx-xx%3B+Galaxy+Nexus+Build%2FIFL10C%29+AppleWebKit%2F534.30+%28KHTML%2C+like+Gecko%29+Version%2F4.0+Mobile+Safari%2F534.30
In Python 3+, You can URL encode any string using the quote() function provided by urllib. parse package. The quote() function by default uses UTF-8 encoding scheme.
replace('%20+', '') will replace '%20+' with empty string.
Use the urllib. parse. urlencode() function (with the doseq parameter set to True ) to convert such dictionaries into query strings.
For Python 2.x, use urllib.quote
Replace special characters in string using the %xx escape. Letters, digits, and the characters '_.-' are never quoted. By default, this function is intended for quoting the path section of the URL. The optional safe parameter specifies additional characters that should not be quoted — its default value is '/'.
example:
In [1]: import urllib In [2]: urllib.quote('%') Out[2]: '%25'
EDIT:
In your case, in order to replace space by plus signs, you may use urllib.quote_plus
example:
In [4]: urllib.quote_plus('a b') Out[4]: 'a+b'
For Python 3.x, use quote
>>> import urllib >>> a = "asdas#@das" >>> urllib.parse.quote(a) 'asdas%23%40das'
and for string with space use quote_plus
>>> import urllib >>> a = "as da& s#@das" >>> urllib.parse.quote_plus(a) 'as+da%26+s%23%40das'
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