I was trying to update values in my dictionary, I came across 2 ways to do so:
product.update(map(key, value)) product.update(key, value)
What is the difference between them?
Python Dictionary update() method updates the dictionary with the elements from another dictionary object or from an iterable of key/value pairs. Syntax: dict.update([other]) Parameters: This method takes either a dictionary or an iterable object of key/value pairs (generally tuples) as parameters.
The UPDATE statement has the following form: UPDATE table_name SET column_name = value [, column_name = value ...] [ WHERE condition]
Python update() method updates the dictionary with the key and value pairs. It inserts key/value if it is not present. It updates key/value if it is already present in the dictionary.
Method 1: Using append() function The append function is used to insert a new value in the list of dictionaries, we will use pop() function along with this to eliminate the duplicate data. Syntax: dictionary[row]['key']. append('value')
The difference is that the second method does not work:
>>> {}.update(1, 2) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: update expected at most 1 arguments, got 2
dict.update()
expects to find a iterable of key-value pairs, keyword arguments, or another dictionary:
Update the dictionary with the key/value pairs from other, overwriting existing keys. Return
None
.
update()
accepts either another dictionary object or an iterable of key/value pairs (as tuples or other iterables of length two). If keyword arguments are specified, the dictionary is then updated with those key/value pairs:d.update(red=1, blue=2)
.
map()
is a built-in method that produces a sequence by applying the elements of the second (and subsequent) arguments to the first argument, which must be a callable. Unless your key
object is a callable and the value
object is a sequence, your first method will fail too.
Demo of a working map()
application:
>>> def key(v): ... return (v, v) ... >>> value = range(3) >>> map(key, value) [(0, 0), (1, 1), (2, 2)] >>> product = {} >>> product.update(map(key, value)) >>> product {0: 0, 1: 1, 2: 2}
Here map()
just produces key-value pairs, which satisfies the dict.update()
expectations.
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