In python3, how do I match exactly whitespace character and not newline \n or tab \t?
I've seen the \s+[^\n]
answer from Regex match space not \n answer, but for the following example it does not work:
a='rasd\nsa sd' print(re.search(r'\s+[^ \n]',a))
Result is <_sre.SRE_Match object; span=(4, 6), match='\ns'>
, which is the newline matched.
\s | Matches whitespace characters, which include the \t , \n , \r , and space characters. \S | Matches non-whitespace characters. \b | Matches the boundary (or empty string) at the start and end of a word, that is, between \w and \W .
If you're looking for a space, that would be " " (one space). If you're looking for one or more, it's " *" (that's two spaces and an asterisk) or " +" (one space and a plus).
The space character does not have any special meaning, it just means "match a space". RE = re. compile(' +') So for your case a='rasd\nsa sd' print(re.search(' +', a))
By using re. DOTALL flag, you can modify the behavior of dot (.) character to match the newline character apart from other characters.
No need for special groups. Just create a regex with a space character. The space character does not have any special meaning, it just means "match a space".
RE = re.compile(' +')
So for your case
a='rasd\nsa sd' print(re.search(' +', a))
would give
<_sre.SRE_Match object; span=(7, 8), match=' '>
If you want to match 1 or more whitespace chars except the newline and a tab use
r"[^\S\n\t]+"
The [^\S]
matches any char that is not a non-whitespace = any char that is whitespace. However, since the character class is a negated one, when you add characters to it they are excluded from matching.
Python demo:
import re a='rasd\nsa sd' print(re.findall(r'[^\S\n\t]+',a)) # => [' ']
Some more considerations: \s
matches [ \t\n\r\f\v]
if ASCII flag is used. So, if you plan to only match ASCII, you might as well use [ \r\f\v]
to exclude the chars you want. If you need to work with Unicode strings, the solution above is a viable one.
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