So somebody showed me how to use condition(s) to test if a user had typed input for a password. I wanna take a their example a step further and use a loop (at least thats what I think it's call).
Here is their example:
read -s -p "Enter new password: " NEWPASS
if test "$NEWPASS" = ""; then
echo "Password CAN NOT be blank re-run sshd_config"
exit 1;
fi
Instead of exiting the script I want it to keep asking for the input until there is some.
I wanna make a statement like this but I was doing it wrong: (Now using top example)
The user is given a chance to enter new password and fill the variable value.
read -s -p "Enter new password:" NEWPASS
echo ""
The next portion checks the variable to see if it contains a value, while the value is null it request the user to fill the value indefinitely. ( a loop)
while [[ -z "$NEWPASS" ]]; do
echo ""
echo "Password CAN NOT be blank"
echo ""
read -s -p "Enter new password:" NEWPASS;
echo ""
done
This line searches a file containing a set of variables used by another file. It then searches the file for a line containing PASS=.* (.* meaning anything) then writes PASS=$NEWPASS ($NEWPASS being variable)
sed -i -e"s/^PASS=.*/PASS=$NEWPASS/" /etc/sshd.conf
Thank you for all the help, I'm going to use this and learn from it.
This while loop should work:
while [[ -z "$NEWPASS" ]]
do
read -s -p "Enter new password: " NEWPASS
done
while read -s -p 'Enter new password: ' NEWPASS && [[ -z "$NEWPASS" ]] ; do
echo "No-no, please, no blank passwords!"
done
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