How Do I Find the Last Positional Parameter in Linux

Question

I am looking to find the last positional parameter. I know to find the number of parameters is $# which logically is the last but I need to find and use what is in the last positional parameter.

It would be like if $# = 5, I want to do $5.

I have tried to do something like $$# or ${$#} as guesses but can't get it.

Instances where I would need to use it is in an if statement or declaring it to another variable or with echo.

I hope that is clear. Thanks in advance.

Answer 1

You want ${!#}, which combines the argument count with indirection.