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If I run this request from my terminal I can see the JSON requests as normally:
curl -XGET 192.168.0.6:8888/scripts/data/backend2/index.php/name/_all My code for the NSURlRequest is this:
NSURLRequest *request = [NSURLRequest requestWithURL: [NSURL URLWithString:@"192.168.0.6:8888/scripts/data/backend2/index.php/name/_all"]]; [[NSURLConnection alloc] initWithRequest:request delegate:self]; And I am getting this error:
didFailWithError 2013-11-29 22:31:08.164 Ski Greece[607:a0b] Connection failed: Error Domain=NSURLErrorDomain Code=-1002 "unsupported URL" UserInfo=0xcd042d0 {NSErrorFailingURLStringKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSErrorFailingURLKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSLocalizedDescription=unsupported URL, NSUnderlyingError=0xdbdcc70 "unsupported URL"} How can I make the call to that URL? I cannot access the server code - I know it is just setup to return me what I need, if I call that URL?
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Unsupported URL" You would receive this error if you are having issues with your data or internet connection, especially with certain WiFi connections. We would advise turning Airplane mode on, then off, to help reset your connection.
Error: "Login Error Unsupported URL" This error can occur if Open Access has been configured with SSL but binding configurations have not been set up within the web. config file. The values for bindingConfiguration and "binding name" are case sensitive and must match.
Try to include appropriate url scheme to your url, e.g.
[NSURL URLWithString:@"http://www...
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In my case I fixed it with this :
strURL = [strURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; strURL contains the string with the URL.
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