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A relatively simple question, but the answer seems to have eluded me. Currently, I have a data frame which looks similar to this:
0 0 0 1 1
0 1 0 1 1
2 1 1 0 3
I'm trying to turn this into a single line of data, by rows. I used the unlist function, and it did what I wanted, but gave them to me by columns. It gave me this:
0,0,2,0,1,1,0,0,1,1,1,0,1,1,3
but what I want is this:
0,0,0,1,1,0,1,0,1,1,2,1,1,0,3
I apologize if this seems like a silly question, but I'm still a novice with R. Any help (or referrals to functions which might help me process this) would be greatly appreciated.
324
To such a list with dataframes, we can also apply the unlist command: As you can see, each column of the data matrix is unlisted itself. It is even possible to unlist a string (i.e. a data object of character class ).
As you can see, each column of the data matrix is unlisted itself. It is even possible to unlist a string (i.e. a data object of character class ). First, let’s modify our list once more: Our new list, my_list_3, consists of three numeric vectors, one data table of the class data.frame, and one character vector.
Pandas provide data analysts a way to delete and filter data frame using dataframe.drop () method. We can use this method to drop such rows that do not satisfy the given conditions. Let’s create a Pandas dataframe. Example 1 : Delete rows based on condition on a column. Example 2 : Delete rows based on multiple conditions on a column.
It is even possible to unlist a string (i.e. a data object of character class ). First, let’s modify our list once more: Our new list, my_list_3, consists of three numeric vectors, one data table of the class data.frame, and one character vector.
We can take the transpose (t) of the dataset and then use c to get a vector output
c(t(df1))
#[1] 0 0 0 1 1 0 1 0 1 1 2 1 1 0 3
By doing transpose, we convert the 'data.frame' to 'matrix'. In both data.frame or matrix, unlist/c operations happen columnwise. So, transposing swaps the columns for rows and viceversa and we get the expected result.
137
You can try also as.vector():
x<-matrix(c(0,0,2,0,1,1,0,0,1,1,1,0,1,1,3),3,5)
x
[,1] [,2] [,3] [,4] [,5]
[1,] 0 0 0 1 1
[2,] 0 1 0 1 1
[3,] 2 1 1 0 3
as.vector(t(x))
[1] 0 0 0 1 1 0 1 0 1 1 2 1 1 0 3
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