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I often use this list command in Unix (AIX / KSH):
ls -Artl
It displays the files as this:
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test1.txt-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 test2.txt
I would like to modify the command such a way that the full path of the file is displayed. For example:
-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test1.txt-rw-r--r-- 1 myuser mygroup 0 Apr 2 11:59 /usr/test2.txt
Any ideas?
I found several resolution methods using pwd or find but - as far as I see - this does not work work if I want to keep the ls options.
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The pwd command displays the full, absolute path of the current, or working, directory.
Use the find command. By default it will recursively list every file and folder descending from your current directory, with the full (relative) path. If you want the relative path, use: find .
An absolute path is the full path to a file or directory. It is relative to the root directory ( / ). Note that it is a best practice to use absolute paths when you use file paths inside of scripts. For example, the absolute path to the ls command is: /usr/bin/ls .
What about this trick...
ls -lrt -d -1 $PWD/{*,.*} OR ls -lrt -d -1 $PWD/* I think this has problems with empty directories but if another poster has a tweak I'll update my answer. Also, you may already know this but this is probably be a good candidate for an alias given it's lengthiness.
[update] added some tweaks based on comments, thanks guys.
[update] as pointed out by the comments you may need to tweek the matcher expressions depending on the shell (bash vs zsh). I've re-added my older command for reference.
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