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I have a text file in which I have something like this-
10.2.57.44 56538154 3028
120.149.20.197 28909678 3166
10.90.158.161 869126135 6025
In that text file, I have around 1,000,000 rows exactly as above. I am working in SunOS environment. I needed a way to remove everything from that text file leaving only IP Address (first column in the above text file is IP Address). So after running some unix command, file should look like something below.
10.2.57.44
120.149.20.197
10.90.158.161
Can anyone please help me out with some Unix command that can remove all the thing leaving only IP Address (first column) and save it back to some file again.
So output should be something like this in some file-
10.2.57.44
120.149.20.197
10.90.158.161
348
1d deletes the first line ( 1 to only act on the first line, d to delete it) $d deletes the last line ( $ to only act on the last line, d to delete it)
Using the sed Command Removing the first line from an input file using the sed command is pretty straightforward. The sed command in the example above isn't hard to understand. The parameter '1d' tells the sed command to apply the 'd' (delete) action on line number '1'.
If delimiter is space character use
cut -d " " -f 1 filename
If delimiter is tab character , no need for -d option as tab is default delimiter for cut command
cut -f 1 filename
-d Delimiter; the character immediately following the -d option is the field delimiter .
-f Specifies a field list, separated by a delimiter
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