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I am using bash to get the IP address of my machine with that script:
_MyGW="$( ip route get 8.8.8.8 | awk 'N=3 {print $N}' )"
And now I am trying to get the Subnet Mask in this type:
192.168.1.0/24
But I have no idea how can I do that.
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In order to find the subnet mask for your host, use the “ifconfig” command with the interface name and pipe it with the “grep” command to isolate the “mask” string. In this case, you are presented with subnet masks for every network interface (loopback interface included).
The command for finding your IP Address is ifconfig. When you issue this command you will receive information for every network connection you have available. Most likely you will see information for both the loopback (lo) and your wired network connection (eth0).
Instead, you could just use this: hostname --all-ip-addresses or hostname -I , which does the same thing (gives you ALL IP addresses of the host).
there are couple of ways to achieve this:
first: to print the mask in format 255.255.255.0, you can use this:
/sbin/ifconfig wlan0 | awk '/Mask:/{ print $4;} '
second: we can use ip command to get the mask in format 192.168.1.1/24
ip -o -f inet addr show | awk '/scope global/ {print $4}'
A better approach will be:
ifconfig eth0 | awk '/netmask/{split($4,a,":"); print a[1]}'
You can substitute the eth0 with any other interface you want
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