Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Unity - Inject different classes for the same interface

I have one interface: IFoo
Two classes implementing that interface: FooOne and FooTwo
And two classes ClassOne and ClassTwo receiving an IFoo parameter in the constructor.

How I configure unity so ClassOne receives a FooOne instance and ClassTwo receives a FooTwo using only one container?

I can't do it at runtime so it must be in the config file.

like image 421
pomber Avatar asked Oct 29 '12 22:10

pomber


2 Answers

Have a look at the Unity documentation.

For a more readable config file you should define type aliases for IFoo, FooOne, FooTwo, ClassOne and ClassTwo. Then you need to register the mappings from IFoo to your implementations. You need to set a name for the mappings. For the consumers of IFoo you need to register an InjectionConstructor.

Your config will look something like this:

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
  <configSections>
    <section name="unity" type="Microsoft.Practices.Unity.Configuration.UnityConfigurationSection,
      Microsoft.Practices.Unity.Configuration"/>
  </configSections>
  <unity xmlns="http://schemas.microsoft.com/practices/2010/unity">
    <alias alias="IFoo" type="UnityConfigFile.IFoo, UnityConfigFile" />
    <alias alias="FooOne" type="UnityConfigFile.FooOne, UnityConfigFile" />
    <alias alias="FooTwo" type="UnityConfigFile.FooTwo, UnityConfigFile" />
    <alias alias="ClassOne" type="UnityConfigFile.ClassOne, UnityConfigFile" />
    <alias alias="ClassTwo" type="UnityConfigFile.ClassTwo, UnityConfigFile" />
    <container>
      <register type="IFoo" name="1" mapTo="FooOne" />
      <register type="IFoo" name="2" mapTo="FooTwo" />
      <register type="ClassOne" mapTo="ClassOne">
        <constructor>
          <param name="foo">
            <dependency type="IFoo" name="1" />
          </param>
        </constructor>
      </register>
      <register type="ClassTwo" mapTo="ClassTwo">
        <constructor>
          <param name="foo">
            <dependency type="IFoo" name="2" />
          </param>
        </constructor>
      </register>
    </container>
  </unity>
</configuration>

That's the corresponding test that shows how it works.

UnityConfigurationSection config =
  (UnityConfigurationSection) ConfigurationManager.GetSection("unity");
IUnityContainer container = new UnityContainer();
container.LoadConfiguration(config);
ClassTwo two = container.Resolve<ClassTwo>();
Assert.IsInstanceOfType(two.Foo, typeof(FooTwo));

Update

At runtime you can do it like this

IUnityContainer container = new UnityContainer();
container.RegisterType<IFoo, FooOne>("One");
container.RegisterType<IFoo, FooTwo>("Two");
container.RegisterType<ClassOne>(new InjectionConstructor(
  new ResolvedParameter<IFoo>("One")));
container.RegisterType<ClassTwo>(new InjectionConstructor(
  new ResolvedParameter<IFoo>("Two")));
like image 60
Sebastian Weber Avatar answered Nov 13 '22 16:11

Sebastian Weber


You need to give them registration names to do this:

// Create an instance of a service you want to use. Alternatively, this
// may have been created by another process and passed to your application
LoggingService myLoggingService = new LoggingService();

// Register the existing object instance with the container
container.RegisterInstance<IMyService>("Logging", myLoggingService);

// Register a mapping for another service your application will use
container.RegisterType<IMyService, myDataService>("DataService");

// When required, retrieve an instance of these services
IMyService theDataService = container.Resolve<IMyService>("DataService");
IMyService theLoggingService = container.Resolve<IMyService>("Logging");

Taken from Resolving Instances Of Types Using Unity

like image 5
Fenton Avatar answered Nov 13 '22 16:11

Fenton