I have a generic class I have created as so:
public abstract class MyClass<T>
{
public T Model
{
get;
protected set;
}
}
And at some point in my code I want to do something with anything of MyClass type. Something like:
private void MyMethod(object param)
{
myClassVar = param as MyClass;
param.Model....etc
}
Is this possible? Or do I need to make MyClass be a subclass of something (MyClassBase) or implement an interface (IMyClass)?
C programming language is a machine-independent programming language that is mainly used to create many types of applications and operating systems such as Windows, and other complicated programs such as the Oracle database, Git, Python interpreter, and games and is considered a programming foundation in the process of ...
In the real sense it has no meaning or full form. It was developed by Dennis Ritchie and Ken Thompson at AT&T bell Lab. First, they used to call it as B language then later they made some improvement into it and renamed it as C and its superscript as C++ which was invented by Dr.
Quote from wikipedia: "A successor to the programming language B, C was originally developed at Bell Labs by Dennis Ritchie between 1972 and 1973 to construct utilities running on Unix." The creators want that everyone "see" his language. So he named it "C".
C is a structured, procedural programming language that has been widely used both for operating systems and applications and that has had a wide following in the academic community. Many versions of UNIX-based operating systems are written in C.
I believe what you are need is to make MyMethod method generic and add constraint on its type parameter:
interface IMyInterface
{
void Foobar();
}
class MyClass<T>
{
public T Model
{
get;
protected set;
}
}
private void MyMethod<T>(MyClass<T> param) where T : IMyInterface
{
param.Model.Foobar();
}
No.
You need to inherit a non-generic base class or implement a non-generic interface.
Note that you won't be able to use the Model
property, since it cannot have a type (unless you constrain it to a base type and implement an untyped property explicitly).
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