I would like results from the second query to override results from the first query:
SELECT "panel_restaurants_restaurant"."id",
"panel_restaurants_restaurant"."name",
"panel_restaurants_restaurant"."logo",
"panel_restaurants_restaurantfeatures"."currency" AS "currency",
ST_DistanceSphere(location, ST_GeomFromText('POINT(0.0 0.0)',4326)) AS "distance",
"panel_meals_meal"."id" AS "meal_id",
"panel_meals_meal"."status" AS "meal_status",
"panel_meals_meal"."available_count" AS "available_dishes",
"panel_meals_meal"."discount_price" AS "discount_price",
"panel_meals_meal"."normal_price" AS "normal_price",
"panel_meals_meal"."collection_from" AS "pickup_from",
"panel_meals_meal"."collection_to" AS "pickup_to",
"panel_meals_meal"."description" AS "meal_description"
FROM "panel_restaurants_restaurant"
INNER JOIN "panel_restaurants_restaurantfeatures" ON (
"panel_restaurants_restaurantfeatures"."restaurant_id" = "panel_restaurants_restaurant"."id")
LEFT OUTER JOIN "panel_meals_meal" ON ("panel_restaurants_restaurant"."id" = "panel_meals_meal"."restaurant_id"
AND "panel_meals_meal"."status" = 0
AND (
("panel_meals_meal"."collection_from" AT TIME ZONE 'Europe/Warsaw')::date = DATE 'today' OR
("panel_meals_meal"."collection_from" AT TIME ZONE 'Europe/Warsaw')::date = DATE 'tomorrow'
)
AND "panel_meals_meal"."collection_to" > '2017-07-29 19:33:47.992075+00:00'
AND "panel_meals_meal"."available_count" > 0)
WHERE "panel_restaurants_restaurant"."status" = 2
UNION
SELECT "panel_restaurants_restaurant"."id",
"panel_restaurants_restaurant"."name",
"panel_restaurants_restaurant"."logo",
"panel_restaurants_restaurantfeatures"."currency" AS "currency",
ST_DistanceSphere(location, ST_GeomFromText('POINT(0.0 0.0)',4326)) AS "distance",
"panel_meals_meal"."id" AS "meal_id",
"panel_meals_meal"."status" AS "meal_status",
"panel_meals_meal"."initial_count" AS "available_dishes",
"panel_meals_meal"."discount_price" AS "discount_price",
"panel_meals_meal"."normal_price" AS "normal_price",
"panel_meals_meal"."collection_from" AS "pickup_from",
"panel_meals_meal"."collection_to" AS "pickup_to",
"panel_meals_meal"."description" AS "meal_description"
FROM "panel_restaurants_restaurant"
INNER JOIN "panel_restaurants_restaurantfeatures" ON (
"panel_restaurants_restaurantfeatures"."restaurant_id" = "panel_restaurants_restaurant"."id")
LEFT OUTER JOIN "panel_meals_meal" ON (
"panel_restaurants_restaurant"."id" = "panel_meals_meal"."restaurant_id" AND
"panel_meals_meal"."status" = 0)
INNER JOIN "panel_meals_mealrepeater" ON (
"panel_meals_mealrepeater"."meal_id" = "panel_meals_meal"."id")
WHERE "panel_restaurants_restaurant"."status" = 2 AND "panel_meals_mealrepeater"."saturday" = true
ORDER BY distance ASC
For example - the first query may return nulls for what comes from the panel_meals_meal table, but the second one will return something - in that situation I will have the same values for id, name, logo, currency, distance and different values (nulls returned from the first query, and something from the other one) for all the other ones.
So the question is - how do I make this UNION distinct on a certain range of columns (actually only one would suffice - id)?
Adding the DISTINCT keyword to a SELECT query causes it to return only unique values for the specified column list so that duplicate rows are removed from the result set. Since DISTINCT operates on all of the fields in SELECT's column list, it can't be applied to an individual field that are part of a larger group.
It returns distinct rows. UNION operator is used for combining result sets from more than one SELECT statement into one result set. Any duplicate rows from the results of the SELECT statements are eliminated.
This SQL UNION ALL example would return the supplier_id multiple times in the result set if that same value appeared in both the suppliers and orders table. The SQL UNION ALL operator does not remove duplicates. If you wish to remove duplicates, try using the UNION operator.
Answer. Yes, the DISTINCT clause can be applied to any valid SELECT query. It is important to note that DISTINCT will filter out all rows that are not unique in terms of all selected columns.
You can do what you want by means of a FULL OUTER JOIN instead of a UNION, and use COALESCE to your advantage.
I simplify your scenario to concentrate on the FULL OUTER JOIN part:
This are the tables (think of them as the result of your first SELECT before whe UNION, and the second SELECT after said UNION):
CREATE TABLE table_a
(
id INTEGER NOT NULL PRIMARY KEY,
name TEXT,
logo TEXT
) ;
CREATE TABLE table_b
(
id INTEGER NOT NULL PRIMARY KEY,
name TEXT,
logo TEXT
) ;
These are the data we have in them:
INSERT INTO
table_a
(id, name, logo)
VALUES
(1, 'Name1-A', 'Logo1-A'),
(2, NULL, NULL),
(3, 'Name3-A', NULL),
(4, NULL, 'Logo4-A'),
(5, 'Name5-only-in-A', NULL);
INSERT INTO
table_b
(id, name, logo)
VALUES
(1, 'Name1-B', 'Logo1-B'),
(2, 'Name2-B', NULL),
(3, 'Name3-B', 'Logo3-B'),
(4, 'Name4-B', 'Logo4-B'),
(6, 'Name6-only-in-B', 'Logo6-B');
The query you're looking for is done by joining in such a way that you retrieve all the rows from both table_a and table_b. Then, you use:
SELECT
id,
COALESCE(a.name, b.name) AS name,
COALESCE(a.logo, b.logo) AS logo
FROM
table_a AS a
FULL OUTER JOIN table_b AS b USING(id)
ORDER BY
id ;
id | name | logo -: | :-------------- | :------ 1 | Name1-A | Logo1-A 2 | Name2-B | null 3 | Name3-A | Logo3-B 4 | Name4-B | Logo4-A 5 | Name5-only-in-A | null 6 | Name6-only-in-B | Logo6-B
dbfiddle here
In your case, substitute table_a AS a by your full first (SELECT ...) AS a, and the same for b. I've assumed id are your primary keys.
References:
FULL OUTER JOINCOALESCEUSING)Using DISTINCT ON, e.g.
SELECT DISTINCT ON (maintenance_task_id)
maintenance_task_id,
execution_count
FROM (
SELECT
id maintenance_task_id,
0 execution_count
FROM maintenance_task
UNION
SELECT
mte1.maintenance_task_id,
count(*) execution_count
FROM maintenance_task_execution mte1
WHERE
mte1.ended_at IS NULL
GROUP BY mte1.maintenance_task_id
) AS t
ORDER BY
maintenance_task_id,
execution_count DESC
In this query:
UNION combines results of two queries.DISTINCT ON picks one row from the top (based on the ORDER BY) for each unique maintenance_task_id value.If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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