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Unable to add element to array in bash

Tags:

arrays

linux

bash

I have the following problem. Let´s assume that $@ contains only valid files. Variable file contains the name of the current file (the file I'm currently "on"). Then variable element contains data in the format file:function.

Now, when variable element is not empty, it should be put into the array. And that's the problem. If I echo element, it contains exactly what I want, although it is not stored in array, so for cycle doesn't print out anything.

I have written two ways I try to insert element into array, but neither works. Can you tell me, What am I doing wrong, please?

I'm using Linux Mint 16.

#!/bin/bash

nm $@ | while read line
do
  pattern="`echo \"$line\" | sed -n \"s/^\(.*\):$/\1/p\"`"
  if [ -n "$pattern" ]; then
    file="$pattern"  
  fi
  element="`echo \"$line\" | sed -n \"s/^U \([0-9a-zA-Z_]*\).*/$file:\1/p\"`"
  if [ -n "$element" ]; then
    array+=("$element")
    #array[$[${#array[@]}+1]]="$element"
    echo element - "$element"
  fi
done

for j in "${array[@]}"
do
  echo "$j"
done
like image 776
user1967718 Avatar asked Mar 27 '14 14:03

user1967718


1 Answers

Your problem is that the while loop runs in a subshell because it is the second command in a pipeline, so any changes made in that loop are not available after the loop exits.

You have a few options. I often use { and } for command grouping:

nm "$@" |
{
while read line
do
    …
done
for j in "${array[@]}"
do
    echo "$j"
done
}

In bash, you can also use process substitution:

while read line
do
    …
done < <(nm "$@")

Also, it is better to use $(…) in place of back-quotes `…` (and not just because it is hard work getting back quotes into markdown text!).

Your line:

element="`echo \"$line\" | sed -n \"s/^U \([0-9a-zA-Z_]*\).*/$file:\1/p\"`"

could be written:

element="$(echo "$line" | sed -n "s/^U \([0-9a-zA-Z_]*\).*/$file:\1/p")"

or even:

element=$(echo "$line" | sed -n "s/^U \([0-9a-zA-Z_]*\).*/$file:\1/p")

It really helps when you need them nested. For example, to list the lib directory adjacent to where gcc is found:

ls -l $(dirname $(dirname $(which gcc)))/lib

vs

ls -l `dirname \`dirname \\\`which gcc\\\`\``/lib

I know which I find easier!

like image 192
Jonathan Leffler Avatar answered Oct 29 '22 17:10

Jonathan Leffler