TypeScript: types for variadic functions [duplicate]

Question

Possible Duplicate:
open-ended function arguments with TypeScript

Is there any acceptable type signature for variadic functions? Example:

function sum () {   var sum = 0;   for (var i = 0; i < arguments.length; i++) {     sum += arguments[i];   }   return sum; };  console.log(sum(1, 2, 3, 4, 5)); 

gives me compilation error:

foo.ts(9,12): Supplied parameters do not match any signature of call target 

Answer 1

In TypeScript you can use "..." to achive the above pattern:

function sum (...numbers: number[]) {   var sum = 0;   for (var i = 0; i <  numbers.length; i++) {     sum += numbers[i];   }   return sum; }; 

This should take care of your error.