typedefs for templated classes?

Question

Is it possible to typedef long types that use templates? For example:

template <typename myfloat_t>
class LongClassName
{
    // ...
};

template <typename myfloat_t>
typedef std::vector< boost::shared_ptr< LongClassName<myfloat_t> > > LongCollection;

LongCollection<float> m_foo;

This doesn't work, but is there a way to achieve a similar effect? I just want to avoid having to type and read a type definition that covers almost the full width of my editor window.

Answer 1

No, that isn't possible currently. It will be made possible in C++0X AFAIK.

The best I can think of is

template<typename T> struct LongCollection {
    typedef std::vector< boost::shared_ptr< LongClassName<T> > > type;
};

LongCollection<float>::type m_foo;

Answer 2

If you don't want to go the macro way you have to make individual typedefs for each type:

typedef std::vector< boost::shared_ptr< LongClassName<float> > > FloatCollection;
typedef std::vector< boost::shared_ptr< LongClassName<double> > > DoubleCollection;