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As the title might look very confusing, let me give you an example:
typedef bool foo[2];
typedef foo bar[4];
bar what_am_i;
So, is what_am_i a [4][2] dimensional array as I presume, or a [2][4] dimensional array?
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In C programming language, typedef is also used with arrays.
A typedef declaration is a declaration with typedef as the storage class. The declarator becomes a new type. You can use typedef declarations to construct shorter or more meaningful names for types already defined by C or for types that you have declared.
The C language contains the typedef keyword to allow users to provide alternative names for the primitive (e.g., int) and user-defined (e.g struct) data types. Remember, this keyword adds a new name for some existing data type but does not create a new type.
A typedef is scoped exactly as the object declaration would have been, so it can be file scoped or local to a block or (in C++) to a namespace or class.
It's bool[4][2]
You can verify it by static_assert:
static_assert(std::is_same<decltype(what_am_i), bool[4][2]>::value, "");
static_assert(std::is_same<decltype(what_am_i), bool[2][4]>::value, ""); // failed
foo is an array with 2 elements of type bool, i.e. bool[2].
bar is an array with 4 elements of type foo, i.e. foo[4], each element is a bool[2].
Then what_am_i is bool[4][2].
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