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How do I get 1324343032.324?
As you can see below, the following do not work:
>>1324343032.324325235 * 1000 / 1000 1324343032.3243253 >>int(1324343032.324325235 * 1000) / 1000.0 1324343032.3239999 >>round(int(1324343032.324325235 * 1000) / 1000.0,3) 1324343032.3239999 >>str(1324343032.3239999) '1324343032.32' 
261
To truncate a number to 3 significant figures, miss off all the digits after the first 3 significant figures (the first non-zero digit and the next two digits). Fill in any spaces with zeros to make the number approximately the same size as the original value.
Use the int Function to Truncate a Float in Python The built-in int() function takes a float and converts it to an integer, thereby truncating a float value by removing its decimal places.
Python's round() function requires two arguments. First is the number to be rounded. Second argument decides the number of decimal places to which it is rounded. To round the number to 2 decimals, give second argument as 2.
You can use an additional float() around it if you want to preserve it as a float.
%.3f'%(1324343032.324325235) You can use the following function to truncate a number to a set number of decimals:
import math def truncate(number, digits) -> float: stepper = 10.0 ** digits return math.trunc(stepper * number) / stepper Usage:
>>> truncate(1324343032.324325235, 3) 1324343032.324 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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