I'm making a project in python and I would like to create a random number that is cryptographically secure, How can I do that? I have read online that the numbers generated by the regular randomizer are not cryptographically secure, and that the function os.urandom(n)
returns me a string, and not a number.
Random numbers and data generated by the random class are not cryptographically protected. An output of all random module functions is not cryptographically secure, whether it is used to create a random number or pick random elements from a sequence.
A PRNG is said to be cryptographically secure if, assuming that it operates over a wide enough unknown n-bit key, its output is computationally indistinguishable from uniformly random bits.
The secrets module is used for generating cryptographically strong random numbers suitable for managing data such as passwords, account authentication, security tokens, and related secrets.
A secure block cipher can be converted into a CSPRNG by running it in counter mode. This is done by choosing a random key and encrypting a 0, then encrypting a 1, then encrypting a 2, etc. The counter can also be started at an arbitrary number other than zero.
Since you want to generate integers in some specific range, it's a lot easier to use the random.SystemRandom
class instead. Creating an instance of that class gives you an object that supports all the methods of the random
module, but using os.urandom()
under the covers. Examples:
>>> from random import SystemRandom
>>> cryptogen = SystemRandom()
>>> [cryptogen.randrange(3) for i in range(20)] # random ints in range(3)
[2, 2, 2, 2, 1, 2, 1, 2, 1, 0, 0, 1, 1, 0, 0, 2, 0, 0, 0, 0]
>>> [cryptogen.random() for i in range(3)] # random floats in [0., 1.)
[0.2710009745425236, 0.016722063038868695, 0.8207742461236148]
Etc. Using urandom()
directly, you have to invent your own algorithms for converting the random bytes it produces to the results you want. Don't do that ;-) SystemRandom
does it for you.
Note this part of the docs:
class random.SystemRandom([seed])
Class that uses the os.urandom() function for generating random numbers from sources provided by the operating system. Not available on all systems. Does not rely on software state and sequences are not reproducible. Accordingly, the seed() and jumpahead() methods have no effect and are ignored. The getstate() and setstate() methods raise NotImplementedError if called.
You can get a list of random numbers by just applying ord
function over the bytes returned by os.urandom
, like this
>>> import os
>>> os.urandom(10)
'm\xd4\x94\x00x7\xbe\x04\xa2R'
>>> type(os.urandom(10))
<type 'str'>
>>> map(ord, os.urandom(10))
[65, 120, 218, 135, 66, 134, 141, 140, 178, 25]
Quoting os.urandom
documentation,
Return a string of
n
random bytes suitable for cryptographic use.This function returns random bytes from an OS-specific randomness source. The returned data should be unpredictable enough for cryptographic applications, though its exact quality depends on the OS implementation. On a UNIX-like system this will query
/dev/urandom
, and on Windows it will useCryptGenRandom()
.
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