too few arguments to function ‘memcpy’ [closed]

Question

what I understand is that memcpy must have 3 arguments:

void * memcpy ( void * destination, const void * source, size_t num );

so I am trying this code:

//char *tmpPtr is a pointer that points to some data
char frameBuffer[921600]; //destination starting a given index
int bufferIndex;//the given index
memccpy(frameBuffer+bufferIndex,tmpPtr,Data.size()-1);

but I am getting this error:

error: too few arguments to function `void * memccpy (void *, const void *, int, size_t)

Answer 1

Typo:

memccpy
   ^^

You called the wrong function.

memccpy also takes a character (as an int argument) upon encountering which the copy shall be stopped.