tidyeval way to programatically send values to filter

Question

Picking up on an earlier thread, (Use string as filter in dplyr?), what would the new tidyeval answer for this be, as filter_ is being deprecated.

Is there a way to use a string variable as the filter argument in dplyr? For example:

filter(iris,Sepal.Length > 6)

would be replaced with

string <- 'Sepal.Length > 6'
filter(iris,string)

Answer 1

Maybe:

filter(iris, !! rlang::parse_expr(string))

But as far as I understand the tidyeval philosophy, code as string is frowned upon and there shouldn't be string <- 'Sepal.Length > 6' in the first place.

Maybe instead:

condition <- expr(Sepal.Length > 6)
filter(iris, !! condition)