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The Thymeleaf 2.1.4 official doc demonstrates the for each usage as below:
<tr th:each="prod : ${prods}" th:class="${prodStat.odd}? 'odd'">
<td th:text="${prod.name}">Onions</td>
<td th:text="${prod.price}">2.41</td>
...
</tr>
It generates one <tr> in each iteration, which is perfect fit in this situation. However in my case I don't need the outer tag (here, <tr>).
My use case is to generating <bookmark> tag in a recursive way, no other tags include, and a <bookmark> tag must contain a name and href attribute.
<!DOCTYPE html SYSTEM "http://www.thymeleaf.org/dtd/xhtml1-strict-thymeleaf-4.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:th="http://www.thymeleaf.org">
<body>
<div th:fragment="locationBookmark(location)">
<bookmark th:each="map : ${location.subMaps}">
<bookmark th:name="${map.name}"
th:href="'#'+${map.id}" th:include=":: locationBookmark(${map})">
</bookmark>
</bookmark>
</div>
</body>
</html>
the including side:
<bookmark th:include="bookmark : locationBookmark(${rootLocation})"/>
Many thanks.
917
Even if it can be done using th:remove="tag" I would suggest you use th:block
<th:block th:each="map : ${location.subMaps}">
<bookmark th:name="${map.name}"
th:href="'#'+${map.id}" th:include=":: locationBookmark(${map})">
</bookmark>
</th:block>
I figured out how to solve the problem, it's easy, just addth:remove="tag" to the outer tag will do.
39
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