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The Difference Between \s and \s+ For example, expression X+ matches one or more X characters. Therefore, the regular expression \s matches a single whitespace character, while \s+ will match one or more whitespace characters.
Example: The regex "aa\n" tries to match two consecutive "a"s at the end of a line, inclusive the newline character itself. Example: "a\+" matches "a+" and not a series of one or "a"s. ^ the caret is the anchor for the start of the string, or the negation symbol.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
*$ means - match, from beginning to end, any character that appears zero or more times. Basically, that means - match everything from start to end of the string. This regex pattern is not very useful. Let's take a regex pattern that may be a bit useful.
.*
. is any char, * means repeated zero or more times.
You can use this regular expression (any whitespace or any non-whitespace) as many times as possible down to and including 0.
[\s\S]*
This expression will match as few as possible, but as many as necessary for the rest of the expression.
[\s\S]*?
For example, in this regex [\s\S]*?B will match aB in aBaaaaB. But in this regex [\s\S]*B will match aBaaaaB in aBaaaaB.
Do you mean
.*
. any character, except newline character, with dotall mode it includes also the newline characters
* any amount of the preceding expression, including 0 times
I would use .*. . matches any character, * signifies 0 or more occurrences. You might need a DOTALL switch to the regex to capture new lines with ..
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