By using (
,)
, you are capturing the group, if you simply remove them you will not have this problem.
>>> str1 = "a b c d"
>>> re.split(" +", str1)
['a', 'b', 'c', 'd']
However there is no need for regex, str.split
without any delimiter specified will split this by whitespace for you. This would be the best way in this case.
>>> str1.split()
['a', 'b', 'c', 'd']
If you really wanted regex you can use this ('\s'
represents whitespace and it's clearer):
>>> re.split("\s+", str1)
['a', 'b', 'c', 'd']
or you can find all non-whitespace characters
>>> re.findall(r'\S+',str1)
['a', 'b', 'c', 'd']
The str.split
method will automatically remove all white space between items:
>>> str1 = "a b c d"
>>> str1.split()
['a', 'b', 'c', 'd']
Docs are here: http://docs.python.org/library/stdtypes.html#str.split
When you use re.split
and the split pattern contains capturing groups, the groups are retained in the output. If you don't want this, use a non-capturing group instead.
Its very simple actually. Try this:
str1="a b c d"
splitStr1 = str1.split()
print splitStr1
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