Swift - Multiple Switch Cases

Question

I am making a board game where you must joins two objects. Each object has a type and there are 5 different types. For each different type combination in a merge, there will be a different effect on the game. Right now, I am working with a switch statement for each combination. So, my code would look something like this.

struct Coin {     var type = 1 }  // Each coin is of type Coin.    switch(coin1.type, coin2.type) {     case (1,1):         functionNormal()     case (1,2):         functionUncommon()     case (1,3):         functionRare()     ... } 

The objects' position doesn't change the result. A (1,2) merge will have the same effect as a (2,1) merge. Is there a less verbose way to achieve this?

Answer 1

You can pass multiple cases as comma separated like

   switch switchValue {     case .none:         return "none"     case .one, .two:         return "multiple values from case 2"     case .three, .four, .five:         return "Multiple values from case 3"     }