Substring substitution in bash

Question

my problem of today is to replace in a string like this --> 6427//6422 6429//6423 6428//6421

every // with a ,. I tried with different commands:

• finalString=${startingString//[//]/,} doesn't work

• fileTemp=$(echo -e "$line\n" | tr "//" "," does a double substitution like this:

  hello//world ---> hello,,world

Someone has an idea of a way to do it?

Answer 1

You can use BASH string manipulations (need to escape / with \/):

s='6427//6422 6429//6423 6428//6421'
echo "${s//\/\//,}"
6427,6422 6429,6423 6428,6421

Similarly using awk:

awk -F '//' -v OFS=, '{$1=$1}1' <<< "$s"
6427,6422 6429,6423 6428,6421

PS: tr cannot be used here since tr translates each character in input to another character in the output and here you're dealing with 2 characters //.

Answer 2

You can use sed as

$ echo "6427//6422 6429//6423 6428//6421" | sed 's#//#,#g'
6427,6422 6429,6423 6428,6421

Answer 3

You can also try the sed command like this

sed 's#/\{2,2\}#,#g'

finds double "/" and replace with ","

Example

echo "6427//6422 6429//6423 6428//6421"| sed 's#/\{2,2\}#,#g'

Results

6427,6422 6429,6423 6428,6421