Subsetting a data.table with a variable (when varname identical to colname)

Question

How can I subset a data.table by using a variable, when the variable name is identical to an existing column name in the data.table? It works with get("varname",pos = 1), but is there are more robust/flexible solution?

library(data.table)

my_data_frame <- data.frame(
"V1"=c("A","B","C","A"),
"V2"=c(1, 2, 3, 4),
stringsAsFactors = FALSE        
)

V1 <- "A"

my_data_table <- as.data.table(my_data_frame)

# Can I improve this a bit? I want rows where V1 == "A", but use V1 in the statement 
my_data_table[ my_data_table$V1 == get("V1", pos = 1), ]

Renaming V1 is not an option.

UPDATE: I do not consider this a 100% duplicate. The accepted answer for this question is not acceptable for my question, since it uses explicit get which I do not want to use, as stated in the comments.

Answer 1

If you don't mind doing it in 2 steps, you can just subset out of the scope of your data.table (though it's usually not what you want to do when working with data.table...):

wh_v1 <- my_data_table[, V1]==V1
my_data_table[wh_v1]
#   V1 V2
#1:  A  1
#2:  A  4

Answer 2

Here is a solution using library(tidyverse):

library(data.table)
library(tidyverse)
my_data_frame <- data.frame(
  "V1"=c("A","B","C","A"),
  "V2"=c(1, 2, 3, 4),
  stringsAsFactors = FALSE        
)

V1 = "A"
my_data_table <- as.data.table(my_data_frame)
df = my_data_table %>% filter(V1 == !!get("V1")) #you do not have to specify pos = 1

If you want to make R use the object named "V1" you can do this

V1 = "A"
list_test = split(my_data_table, as.factor(my_data_table$V1)) #create a list for each factor level of the column V1.
df = list_test[[V1]] #extract the desired dataframe from the list using the object "V1"

Is it what you want?