Store an integer value in a character array in C

Question

It is a very trivial question but I don't know why I am not getting the correct output. Here is what I am trying to do:

char sendBuffer[1000];
int count=0:
while(count<10)
{
    sendBuffer[0]=count;
    sendBuffer[1]='a';
    sendBuffer[2]='b';
    sendBuffer[3]='c';
    sendBuffer[4]='\0';
    printf(%s,sendBuffer);
    count=count+1;
}

In the output, all buffer is printed correctly except the first index. I want 1,2,3 and so on to be printed at the start of the buffer but it does not work. Please Help

Answer 1

You need to convert that number into a character. A cheap way to do it is:

sendBuffer[0] = '0' + count;

is there anyway to display integers greater than 9

If you need that you'll want to shift to more elaborate schemes. For example, if you want to convert an integer 42 into the string "42" you can say:

#define ENOUGH ((CHAR_BIT * sizeof(int) - 1) / 3 + 2)

char str[ENOUGH];
snprint(str, sizeof str, "%d", 42);

Credit for ENOUGH goes to caf.