I'm having trouble with std::initializer_list. I reduced it down to a simple example:
#include <initializer_list>
#include <cstdio>
class Test {
public:
template <typename type> Test(const std::initializer_list<type>& args) {}
};
int main(int argc, char* argv[]) {
Test({1,2});
getchar();
return 0;
}
When compiled using g++ test_initializer.cpp -std=c++0x
, it compiles and runs well. However, if line 11 is changed to Test({1,2.0});
, one gets:
ian@<host>:~/Desktop$ g++ test_initializer.cpp -std=c++0x
test_initializer.cpp: In function ‘int main(int, char**)’:
test_initializer.cpp:11:14: error: no matching function for call to ‘Test::Test(<brace-enclosed initializer list>)’
test_initializer.cpp:11:14: note: candidates are:
test_initializer.cpp:7:28: note: template<class type> Test::Test(const std::initializer_list<_Tp>&)
test_initializer.cpp:5:7: note: constexpr Test::Test(const Test&)
test_initializer.cpp:5:7: note: no known conversion for argument 1 from ‘<brace-enclosed initializer list>’ to ‘const Test&’
test_initializer.cpp:5:7: note: constexpr Test::Test(Test&&)
test_initializer.cpp:5:7: note: no known conversion for argument 1 from ‘<brace-enclosed initializer list>’ to ‘Test&&’
I suspect this happens because the compiler can't figure out what type to make the initializer list. Is there a way to fix the example so that it works with different types (and still uses initializer lists)?
An std::initializer_list
takes only one type. If you need different types, you can use variadic templates:
template<typename... Args>
Test(Args&&... args);
/* ... */
int main()
{
Test(1, 2.0);
}
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