I am currently trying to use std::bind
to create a std::function<void()>
from the function template
template<class Iterator>
void printRange(Iterator first, Iterator last) {
std::copy(first, last, std::ostream_iterator<typename Iterator::value_type>(std::cout, " "));
std::cout << std::endl;
}
Conceptually, what I want is
int main() {
std::vector<int> v{1, 2, 3};
auto f0 = std::bind(printRange, v.begin(), v.end()); // won't compile, of course
f0();
return 0;
}
I understand that this does not compile and I have to instantiate the function template before I can actually use it. For example, the following alternatives would work:
auto f1 = std::bind(printRange<std::vector<int>::const_iterator>, v.begin(), v.end());
auto f2 = std::bind(printRange<decltype(v.begin())>, v.begin(), v.end());
auto f3 = [&v]() { printRange(v.begin(), v.end()); };
I already created a convenience function
template<class Iterator>
std::function<void()> makePrintRangeFunction(Iterator first, Iterator last) {
return std::bind(printRange<Iterator>, first, last);
}
to ease the process:
auto f4 = makePrintRangeFunction(v.begin(), v.end());
I wonder if it is possible to create a more generic std::function<void()>
generator, accepting a function template as a first argument and the function template arguments as a variable-length argument list? If not using built-in language features, maybe via a macro?
Templates Specialization is defined as a mechanism that allows any programmer to use types as parameters for a class or a function. A function/class defined using the template is called a generic function/class, and the ability to use and create generic functions/classes is one of the critical features of C++.
std::bind is for partial function application. That is, suppose you have a function object f which takes 3 arguments: f(a,b,c); You want a new function object which only takes two arguments, defined as: g(a,b) := f(a, 4, b);
A function template starts with the keyword template followed by template parameter(s) inside <> which is followed by the function definition. In the above code, T is a template argument that accepts different data types ( int , float , etc.), and typename is a keyword.
Function templates are similar to class templates but define a family of functions. With function templates, you can specify a set of functions that are based on the same code but act on different types or classes. The following function template swaps two items: C++ Copy.
As long as you do not need to have template function return type, you can do this:
#include <functional>
#include <iostream>
#include <typeinfo>
template<typename ... T>
std::function<void()> makePrintRangeFunction(void (*f)(T...), T... param) {
return std::bind(f, param...);
}
template<typename T, typename V>
void print(T type, V val)
{
std::cout << typeid(type).name() << '\n' << val << '\n';
}
int main()
{
int i = 5;
double d = 10.5;
auto f = makePrintRangeFunction(print, i, d);
f();
}
Maybe the following code will help :)
template <class F, class... Args>
void test(F&& f, Args&&... args) {
std::function<typename std::result_of<F(Args...)>::type()> task(
std::bind(std::forward<F>(f), std::forward<Args>(args)...));
task();
}
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