I have an object which holds a unique_ptr and as such can't be copy constructed without doing a deep copy (which I don't want).
I'd like to have std::any hold that object, but the only alternatives I've found is to either make std::any hold a pointer, which adds a useless indirection, or make my object have a unique ptr. The code bellow will hopefully illustrate my point:
//Compiled with clang++ -std=c++2a; clang version 5.0.0
#include <iostream>
#include <any>
#include <memory>
struct A {
std::unique_ptr<int> m = std::make_unique<int>(11);
A(A&& a): m(std::move(a.m)) {}
A() {}
};
struct B {
std::shared_ptr<int> m = std::make_shared<int>(11);
};
template<class T>
void use_any_ptr() {
std::any a{new T{}};
std::cout << *(std::any_cast<T*>(a)->m) << std::endl;
}
template<class T>
void use_any() {
std::any a{T{}};
std::cout << *(std::any_cast<T>(a).m) << std::endl;
}
int main() {
use_any_ptr<A>(); // Workaround using a pointer
use_any<B>(); // Workaround using shared pointer
use_any<A>(); // Breaks because A has no cc no matching constructor for initialization of 'std::any'
}
As far as I understand the construction of std::any seems to require copying of the object, however I'm unsure why the object couldn't simply be moved.
Is there a way to work around this ? That is, other than using a shared_ptr, which means I'm basically expressing the "wrong thing" for the sake of creating the any object or passing std::any a pointer (which is an unneeded level of indirection, since std::any holds a void pointer to the type to being with as far as I can tell).
Is there a different implementation of any that could use the move ctr at creation instead of the copy ctr ?
Or am I being silly and not understanding the "real" problem here ?
A cleaner solution: create a class where the default copy constructor and/or default copy assignment operator are deleted. Derive all your classes or the base class of the class hierarchies from this special class. Copy construction and/or copy assignment will now be disabled for all these classes automatically.
The problem is simple here: std::any has a copy constructor and thus it requires the object contained is copy constructible.
Copy Constructor in C++ Copy constructor is used to initialize the members of a newly created object by copying the members of an already existing object. Copy constructor takes a reference to an object of the same class as an argument.
Or am I being silly and not understanding the "real" problem here ?
The problem is simple here: std::any
has a copy constructor and thus it requires the object contained is copy constructible.
The way you can work around it is by defining a custom object that contains the pointer, that is copyable and that implements a proper logic for it (whatever proper means in your case, I can't see how you could copy an std::any
and thus an object contained there that owns an std::unique_ptr
, but maybe you can get away with it somehow in your case).
Otherwise rethink your design and try to get rid of the need of an std::any
. It hasn't much uses indeed and probably you can get the same with a bit of template machinery or an std::variant
or whatever
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